Question

A man moves on a straight horizontal road with a box of mass 2kg in his hand. If he moves a
distance of 40m in 2 sec with an acceleration of 0.5m/s?, calculate the work done by the man on
the box during motion and power.​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Work\:done=40J }}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Mass (m) = 2kg

• Distance (s) = 40m

• Time (t) = 2sec

• Acceleration (a) = 0.5$\sf{m/{s}^{2}}$

$\large\underline\pink{\sf To\:Find: }$

• Work done by man on box = ?

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We know that ,

According to Newtons second law of motion :-

$\large{♡}$$\large{\boxed{\sf F=ma }}$

F = Force

m = mass

a = Acceleration

On Putting value :

$\large\implies{\sf F=2×0.5 }$

$\large\boxed{\sf F= 1N}$

_________________________________________

$\large{♡}$$\large{\boxed{\sf Work\:Done(W)=F.ds}}$

$\large\implies{\sf W=1×40 }$

$\large{\sf W=40J }$

$\huge\red{♡}$$\large\red{\boxed{\sf Work\:done=40J }}$