Question

a man moves with constant acceleration 5m/s2 from the rest. Find out the distance covered in last 9 seconds​

Answer 1

Answer :- The distance travelled is 202.5 m

Step by Step Explanation :-

•Given that

▪Acceleration (a) → 5 m/s²

▪Initial Velocity (u) → 0 [ as it starts from rest. ]

▪Time (t) → 9 seconds

⚫Using the second Equation of Motion

S = ut + ½ at²

S = 0 × 9 + ½ × 5 × (9)²

S = ½ × 5 × 81

=> 202.5

•°• The distance travelled in the last 9 seconds is 202.5 m!

_______________________________________________