Physics, asked by gatturamakrishna1, 10 months ago

A man moving with a speed v
down the inclined plane
meets the rain horizontally
with same speed. The actual
velocity of rain is

Answers

Answered by johann512
1

Answer:

Explanation:

Given,

= v₀cos37°(-i) + v₀sin37°(j)  

= -4v₀/5 i + 3v₀/5 j  

and  = 2v₀ i  

Hence,  

=2v₀i +(-4v₀/5 i + 3v₀/5 j)  

= 6v₀/5 i + 3v₀/5 j ----(1)

Now, velocity of man with respect to ground, ​ = -2v₀cos37° i + 2v₀sin37°j  

= -8v₀/5 i + 6v₀/5 j  

​ = 6v₀/5 i + 3v₀/5 j -(- 8v₀/5 i + 6v₀/5 j)

= 14v₀/5 i - 3v₀/5 j

Now, | | = √{(196 + 9)/25}v₀ = √{205/25}v₀ =√(41/5)v₀

Hence, n =41

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