Question

A man observes the angle of elevation of the top of a building to be 30 degrees. He walks towards it in a horizontal line through its base. On covering 60m, the angle of elevation changes to 60 degrees. Find the height of the building correct to the nearest metre.


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Answer 1

: Required Answer

: Given

➝ elevation of the top of a building to be 30 degree

➝ On covering 60m, the angle of elevation changes to 60 degrees.

: Find

it's height of the building correct to the nearest metre.

: Solution

$\implies$ let the height be h

$\implies$ In ∆ BCD h/x = 60°

$\implies$ h/x = √3

$\implies$ h = √3 x

$\implies$ In ΔACD, h(x+60 ) = tan30°

$\implies$ h/ (x+60) = 1/ √3

$\implies$ h √3 = x+ 60

$\implies$ 3x - ×=60

$\implies$ 2x =60

$\implies$ x = 30

$\implies$ Now , h = √3x

$\implies$ h = 30 × √3

$\implies$ 30 ×√3

$\implies$ 30 × 1.732

$\implies$ 51.96 m

Hence the 51.96 m is the nearest meter :)

Answer 2

Step-by-step explanation:

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