a man of 1.5 m height is standing at a distance of 10
cm from a building if the angle of elevation for his eyes to the top of the building is 60 degree find the height of the building
manjushree33:
please answer fast because tomorrow there is an exam
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the height of building h=10.160
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I think the answer is wrong because u have taken cosA in the place of tanA. as opposite /adjacent
oops... tanA=h-1.5/10root3 》h-1.5=tan60'×10root3 ;;h=31.5
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