Question

A man of 1.5 meters height is standing at a distance of 10 root 3meter from a building. If the angle of elavation from his eyes to the top of the building is 60 degree.Find the height of the building.​

Answer 1

Answer:

hope it is helpful

Answer 2

Answer:

Let AC be the tower, CFG be the ground, DHB be the line of sight and GD be the original position of the boy from the building.

∴AC=30m and DG=BC=1.5m

Let FH be the new position of the boy.

Now, AC=AB+BC

∴AB=AC−BC

∴AB=30−1.5=28.5m

In △ABD,

tan30

o = BD

AB = BD

28.5

31 = BD28.5

∴BD=28.5 3 m

In △ABH,

tan60

o = BH

AB

BH= 3

28.5 × 33

=9.53m

Now, DH=BD−BH

∴DH=28.5

3 −9.53

∴DH=18

3m