Question

A man of 100 kg mass is standing on the the earth of mass 6x10^24 kg & radius 6,400 km. Calculate the gravitational force between them .​

Answer 1

$\blue{\mathfrak{\underline{\large{Given}}}:} \\ mass \: of \: the \: man(m_1) = 100 \: kg = {10}^{2} \: kg \\ mass \: of \: the \: earth(m_2) = 6 \times {10}^{24} \: kg \\ radius \: of \: earth(r) = 6400km \\ = 6400 \times 1000 \: m \\ = 6.4 \times {10}^{6} \: m \\ gravitation \: constant(G) = 6.67 \times {10}^{ - 11} N { m }^{2} {kg}^{ - 2} \\\blue{\mathfrak{\underline{\large{To \: find}}}:} \\ gravitational \: force \: between \: m_1 \: and \: m_2 \\ (F_g) = ? \\ \blue{\mathfrak{\underline{\large{Finding}}}:} \\ F_g = G \frac{m_1m_2}{ {r}^{2} } \\\\ = \frac{6.67 \times {10}^{ - 11} \times {10}^{2} \times 6 \times {10}^{24} }{ {(6.4 \times {10}^{6})}^{2} }\\ \\ = \frac{40.02 \times {10}^{ - 11 + 2 + 24} }{40.96 \times {10}^{12} } \\ \\ = \frac{40.02}{40.96} \times {10}^{15 - 12} \\ \\ = 0.977 \times {10}^{3} \\ \\≈977 \: N \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$