Question

a man of 1kg at a height 'h' has potential energy of 98 joule. what is it's height?

class: 9​

Answer 1

Answer:Answer:

The Object is at height (h) = 0.102 meters.

Given:

Mass of the Body (m) = 1 Kg.

Potential energy (E) = 1 Joule.

Acceleration Due to Gravity (g) = 9.8 m/s²

Explanation:

Potential Energy:-

Potential energy is the energy which a body posses due to virtue of Position.

Formula of Potential energy

P.E = Mgh

M denotes Mass of the Body.

g denotes Acceleration Due to Gravity.

h Denotes the Height to which the body is raisen.

____________________________

From Potential energy Formula,

⇒ P.E = Mgh

⇒ E = M x g x h

⇒ E = 1 kg x 9.8 m/s² x h meters

⇒ E = 1 x 9.8 x h

⇒ E = 9.8 x h

∵ [ Potential Energy = 1 joule.]

Substituting,

⇒ 1 = 9.8 x h

⇒ h = 1/9.8

⇒ h = 10/98

⇒ h = 0.102 Meters.

So, The Height at which Potential Energy is 1 joule is 0.102 meters.

Note:-

Here I took Acceleration Due to gravity(g) as 9.8 m/s².

If you take  g = 10 m/s² , The final answer comes as 0.1 meters.

Answer 2

Answer:-

10m

Explanation:-

Given:

Mass,m = 1kg

Potential engery,PE = 98 J (ATQ)

To Find:

Height = ?

Solution:

Energy possessed by an object because of its position is called potential energy.

We know,

PE = mgh

Note: g = acceleration due to gravity.

Put their values and find “h”

$\sf{}\implies 98 J = 1kg \times 9.8m/s^2 \times h$

$\sf{}\implies h=\dfrac{98 J}{9.8kgm/s^2}$

$\sf{}\implies h=98 J \div 9.8kgm/s^2}$

$\sf{}\implies h=98 J \div \dfrac{98}{10}kgm/s^2}$

$\sf{}\implies h=98 J \times \dfrac{10}{98}kgm/s^2}$

$\sf{}\implies h=10m$

Therefore height is equal to 10m