Question

a man of 50 kg carries a child of 10 kg on his shoulder at a hight 1m from the ground if a man moves with a speed 0.5 m/s the total energy is​

Answer 1

Explanation:

Let the speed of the man in upward direction be V.

Applying conservation of linear momentum of man and stone system : P

f

=P

i

M

man

V−M

stone

V

stone

=0

Or 50V−0.5×2=0

⟹ V=0.02 m/s

Time taken by stone to reach the ground t=

2 m/s

10 m

=5 s

Distance covered by man in 5 s, d=Vt=0.02×5=0.1 m (in upward direction)

Thus distance of man above the floor h=10+0.1=10.1 m