A man of 50 kg mass is standing in a gravity free space
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A man who is standing in zero gravity space will not experience any force due to gravitational force by other massive bodies.
In Zero gravity, a body cannot experience any weight.
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Answer:
Let the speed of the man in upward direction be V.
Applying conservation of linear momentum of man and stone system : P
f
=P
i
M
man
V−M
stone
V
stone
=0
Or 50V−0.5×2=0
⟹ V=0.02 m/s
Time taken by stone to reach the ground t=
2 m/s
10 m
=5 s
Distance covered by man in 5 s, d=Vt=0.02×5=0.1 m (in upward direction)
Thus distance of man above the floor h=10+0.1=10.1 m
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