Question

a man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. he trows a stone of 0.5 kg mass downwards with a speed 2m/s .when the stone reaches the floor,the distance of thr man above the floor will be

Answer 1

Hello Surbhi,
Mark this answer as brainliest if you are satisfied.

As there is no gravity, there will be no acceleration and so you can simply use the momentum conservation theorem.

Let the speed of man after throwing the man be v :

p initial = p final
> 0 = 50v - ½×2
> v = 1/50 m/s

Time taken by stone to reach the floor = distance ÷ speed (stone) = 10/2 = 5 sec

Distance travelled by man in that time = Speed of man × time taken by stone = (1/50) × 5 = 0.1 meter

Total distance of man from floor = 10 + 0.1 = 10.1 meters

Thanks !