Question

A man of a father is three times the sum of the ages of his two sons. 24 year hence,the age of the father will be equal to the sum of the ages of his sons. Find the present age of the father

Answer 1

Answer:

Step-by-step explanation:

let age of sons be x and y

age of father= 3(x+y)

24 years later,

  age of 1st son = x+24

  age of 2nd son = y+24

   age of father= 3x+3y+24

A/Q,

        3x+3y+24 = x+24+y+24

         2x+2y = 24

          x+ y = 12

Age of father = 3(x+y)

                       = 3*12

                       =36

Answer 2

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20