Question

A man of height 1.5m sees top of the tree at an angle of elavation 50 (degree) the distance between tree and man is 5m what is the height of the tree​

Answer 1

Answer:

7.46m

Step-by-step explanation:

for diagram refer image attached

$\tan( \alpha ) = \frac{bc}{ab}$

$\tan(50) = \frac{bc}{5}$

$bc = 5.95m$

ht of tree = bc + bd = 5.95 + 1.5= 7.45m