Question

a man of height 1.8 m stands in semicircle at with distance of 0.9m to one end find width of Arc and his head touches the arc..

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Answer 1

Step-by-step explanation:

Given a man of height 1.8 m stands in semicircle at with distance of 0.9 m to one end find width of Arc and his head touches    

• By Pythagoras theorem we get
• So r^2 = (1.8)^2 + (r – 0.9)^2
•          = (1.8)^2 + r^2 – 1.8 r + 0.9^2
• So 1.8 r = (1.8)^2 + (0.9)^2
•             = 3.24 + 0.81
• So 1.8 r = 4.05
• Or r = 4.05 / 1.8
• So r = 2.25
• Now d = 2r
•             = 2 x 2.25

Or d = 4.5 m  

Reference link will be

https://brainly.in/question/8415281