a man of height 156 cm stands under the semicircular arc at a distance of 36 cm from one end such that is head touches the Arc find the width of arc
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26
Answer:
Radius = 356 cm
Diameter = 712 cm
Step-by-step explanation:
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Answer:
Step-by-step explanation:ysquare=156square+36square
Zsquare=xsquare+156square
Zsquare +ysquare =(x+36)square. (Angle inscribed in a semicircle is 90)
Xsquare +36square +2×156square = xsquare +2×xx36+36square(comparing equations)
X=676
Width =676+36=712
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