A man of height h is walking away from the street lamp of height 3h with constant speeh v find the rate at which of thr lenght of the shadow of the man is increasing when he is at a distance of 10h from the base of the lamp
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Let the horizontal distance between lamp and person be a and the horizontal distance between person and shadow be b From the figure: ΔABC and δADE are similar DEBC=AEAC ⇒3hh=a+bb ⇒3b=a+b ⇒a=2b Differentiating on both sides w.r.t. t ∂a∂t=∂ 2b∂t ⇒vman=2×vshadow ⇒vshadow=v2
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