Physics, asked by yash602184, 11 months ago

A man of mass 2m is pulling up a block of mass m with constant
velocity. The acceleration of man is (neglect any friction).
(a)g
(b) 29
(c) 38
(d) &​

Answers

Answered by Rohitpoul
5

Explanation:

accn is g because their is constant velocity

Answered by archanajhaasl
0

Answer:

The acceleration of man is \frac{g}{2} .

Explanation:

The tension on the block is given as,

T=m(g+a)     (1)

Where,

T=tension

m=mass of the block

g=acceleration due to gravity

a=acceleration of the block

Since the velocity is constant the acceleration i.e.a will be zero. Equation (1) can be expressed as follows:

T=m(g+0)

T=mg        (2)

And the tension supplied by the rope to the man is calculated as,

T=2m\times a'     (3)

a'=acceleration of the man

By equalizing equations (2) and (3) we get;

mg=2m\times a'

a'=\frac{g}{2}

The acceleration of man is \frac{g}{2} i.e.none of the options is correct.

#SPJ2

Similar questions