A man of mass 30 kg uses a rope to climb which bears only 450 N. What is the maximum acceleration with which he can climb safely? ( Ans: 15 m/s² )
Answers
Answered by
87
Given,
Mass=30kg
Force=450N
as we know,
force=mass×acceleration
450=30×a
450=30a
a=450/30
a=15m/s^2 (Ans)
Mass=30kg
Force=450N
as we know,
force=mass×acceleration
450=30×a
450=30a
a=450/30
a=15m/s^2 (Ans)
Answered by
2
Answer:
The maximum acceleration with which the man can climb safely is 15m/s².
Explanation:
Given:
Mass(m) = 30kg
Force(F) = 450N
To find:
Acceleration(a) =?
Formula:
Force = Mass × Acceleration
Solution:
We know that force is given as the product of mass and acceleration.
Here, the mass of the man is given to be 30kg, and the rope can bear up to 450N.
Substituting the given values in the above formula, we get
Force = Mass × Acceleration
450 = 30 × a
a = 450/30
a = 15
Acceleration = 15m/s²
Therefore, the maximum acceleration is 15m/s².
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