Question

A man of mass 40 kg is at rest between the walls. If co eff. of friction between man and wall is 0.8, find the normal reaction exerted by wall on man (take g = 10 m/s/s)

Answer 1

Let coefficient of friction be ω

Force of friction = K

Normal reaction = N

Formula :

ω = K / N

K = 40 × 10 = 400 N

0.8 = 400 / N

0.8 N = 400

N = 400 / 0.8

N = 500 N

Normal reaction is :

500N.

Answer 2

Answer:

Explanation:

Let coefficient of friction be ω

Force of friction = K

Normal reaction = N

Formula :

ω = K / N

K = 40 × 10 = 400 N

0.8 = 400 / N

0.8 N = 400

N = 400 / 0.8

N = 500 N

Normal reaction is :

500N.