a man of mass 40 kg is at rest between the world if the coefficient of friction between the man and the wood is 0.8 find the normal reaction is it by the wall on man
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Answer:
Hii dear here is ur answer
Let coefficient of friction be ω
Force of friction = K
Normal reaction = N
Formula :
ω = K / N
K = 40 × 10 = 400 N
0.8 = 400 / N
0.8 N = 400
N = 400 / 0.8
N = 500 N
Normal reaction is :
500N.
Hope its help u
manjeetverma1:
wrong answer is 250 bcz wall is on both side the men
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