a man of mass 40 kg is running with the velocity of 10m/sec^ he jumped over a stationary cart of 10kg while running find the velocity of cart
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Answer:
M = mass of the boy = 50 kg
V = initial velocity of the boy before jumping into cart = 2 m/s
m = mass of stationary cart = 2 kg
v = velocity of stationary cart = 0 m/s
V' = velocity of boy and cart combination after collision
Using conservation of momentum
M V + m v = (M + m) V'
(50) (2) + (2) (0) = (50 + 2) V'
V' = 100/52
V' = 1.92 m/s:
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