Question

A man of mass 50 kg is pulling on a plank of mass 100 kg kept on a smooth floor as
shown with force of 100N. If both man & plank move together, find force of friction acting
on man.
50 kg
V= 1/6
G
100
=0
(A) 190 N towards left
(C) 250 N towards left
(B) 190 N towards right
(D) 250 N towards right​

Answer 1

Answer:

......

Explanation:

The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards.

So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.

Let the common acceleration = a m/s^2

Man: net force = T - f = m a = 50 a

Plank: net force = T + f = m a = 100 a

As T = 100 N, a = 4/3 m/s^2 and f = 100/3 Newtons.

Answer 2

Answer:

option c

hope this will helps u....

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