a man of mass 50 kg is standing on a hundred kg plant kept on frictionless horizontal so initially both are at rest the man starts walking on plan with Speed 6 metre per second towards right
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Let the velocity of plank be v leftwards
Therefore velocity of man is (6-v) rightwards
According to conservation of linear momentum
100v =50(6-v)
Therefore,
v=2m/s
As work gain in kinetic energy is equal to muscle energy spent 1/2*100*2^2 + 1/2*50*4^2 =600 J
Therefore velocity of man is (6-v) rightwards
According to conservation of linear momentum
100v =50(6-v)
Therefore,
v=2m/s
As work gain in kinetic energy is equal to muscle energy spent 1/2*100*2^2 + 1/2*50*4^2 =600 J
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