A man of mass 50 kg slowly climbs a vertical height of 3600 m in 1 hour. The average power expended by the man against gravity is [Take g = 10 m/s²]
Answers
Given : A man of mass 50 kg slowly climbs a vertical height of 3600 m in 1 hour.
g = 10 m/s²
To Find : The average power expended by the man against gravity
Solution:
Work Done = mgh
m = 50 kg
g = 10 m/s²
h = 3600 m
Work Done = 50 * 10 * 3600
= 1800000 Joule
Power = Work Done / time
Time = 1 hr = 3600 sec
Power = 1800000/3600 J/s
= 500 J/s
= 500W
The average power expended by the man against gravity = 500W
Learn More:
In a new system of units, unit of mass is taken as100 kg, unit of ...
brainly.in/question/18852647
What is the current in SI unit if+100 coulombs of charge flows past a ...
brainly.in/question/11845618
Answer:
Work Done = mgh
m = 50 kg
= 10 m/s² g=
h = 3600 m
Work Done = 50 * 10 * 3600
= 1800000 Joule
Power = Work Done / time
Time 1 hr = 3600 sec
Power = 1800000/3600 J/s
= 500 J/s
= 500W.
The average power expended by the man against gravity = 500W.