Question

A man of mass 50 kg stands at the rim of a turntable of radius 2 m, and moment of inertia 4000 kg m2mounted on a vertical frictionless shaft at its centre. The whole system is initially at rest. The man now walks along the outer edge of turntable with a velocity of 1 m/s clockwise relative to earth. The angular velocity of turntable is​

Answer 1

Answer:

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Explanation:

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Answer 2

Thus the angular velocity of the turntable is 0.5 rad / second

Explanation:

Mass of man = 50 Kg

Radius of turntable =  2 m

Moment of inertia = 4000 Kg m^2

Velocity of turntable = 1 m/s

To find: Angular velocity of turntable "ω" = ?

V = rω

ω = V / r

ω = 1 / 2 = 0.5 rad / s

Thus the angular velocity of the turntable is 0.5 rad / second