A man of mass 50kg is standing on a 100kg plank kept on a frictionless horizontal floor. initially both are at rest. if the man starts walking on the plank with the speed 6m/s, towards the right relative to the plank, then amount of muscle energy spent by the man is?
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Because it has kinetic energy
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Answer:
Explanation: K.E = 1/2 MV^2
K.E = 1/2 ×50×6^2
K.E = 900 KG.M^2/$^2
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