Question

a man of mass 50kg is standing on a 100kg plank kept on a frictionless horizontal floor. initially both are at rest. if the man starts walking on the plank with speed 6m/s towards right relative to the plank, then amount of muscle energy spent by the man is?​

Answer 1

Answer:

Explanation:

Let the velocity of plank be v leftwards Therefore velocity of man is (6-v) rightwards There according to conservation of linear momentum 100v =50(6-v) Therefore, v=2m/s As work gain in kinetic energy is equal to muscle energy spent 1/2*100*2^2 + 1/2*50*4^2 =600 J

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Answer 2

Answer:

Explanation:

Here is soln given