Question

A man of mass 50kg is walking east to west on a level road (acceleration due to gravity, g=10m/s^2) .What is the frictional force acting when the man was standing on the road?

Answer 1

Answer:-

• Mass=50kg
• Acceleration due to gravity=10m/s^2

According to Newtons Second law

$\boxed{\sf Force=Mass\times Acceleration}$

$\\ \sf\longmapsto Force=50\times 10$

$\\ \sf\longmapsto Force=50kgm/s^2$

$\\ \sf\longmapsto Force=50N$

Hence forth

Frictional force acting on the man while standing on the road is 50N.

Note:-

• SI unit of Force is Newton.
• It is indicated as N
• It is named after one of the great scientists of the world I.e Eizak Newton who is known as Inventor of Gravitation.

Answer 2

Answer: W=mg= 50*10=500N

Explanation:

Newton's 2nd law of motion