Question

A man of mass 50kg is walking from East to West direction on a leveled road. acceleration due to gravity g=10m per second sq. What is the frictional force acting when the man is standing on the road?​

Answer 1

Answer:

Answer:

• Mass=50kg

• Acceleration due to gravity=10m/s^2

According to Newtons Second law

Force

Mass x Acceleration

4G all 67

Force = 50 x 10

Force

50kgm/s²

Force = 50N

Hence forth

Frictional force acting on the man while standing on the road is 50N.

Answer 2

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Answer:-

Mass=50kg

Acceleration due to gravity=10m/s^2

According to Newtons Second law

\boxed{\sf Force=Mass\times Acceleration}

Force=Mass×Acceleration

\begin{gathered}\\ \sf\longmapsto Force=50\times 10\end{gathered}

⟼Force=50×10

\begin{gathered}\\ \sf\longmapsto Force=50kgm/s^2\end{gathered}

⟼Force=50kgm/s

2

\begin{gathered}\\ \sf\longmapsto Force=50N\end{gathered}

⟼Force=50N

Hence forth

Frictional force acting on the man while standing on the road is 50N.

Note:-

• SI unit of Force is Newton.
• It is indicated as N
• It is named after one of the great scientists of the world I.e Eizak Newton who is known as Inventor of Gravitation.

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