A man of mass 56 kg is standing on a weighing
machine kept on the floor of a lift which is moving
down with acceleration 2 m/s2. The apparent
weight of the man is (g = 10 m/s2)
(1) 700 N
(2) 660 N
(3) 560 N
(4) 448 N
Answers
Answered by
2
Explanation:
the answer is 3 560n I hope its help you
Answered by
5
Answer:
448 N
Explanation:
Lift is moving down so a pseudo acceleration must work upward with same magnitude and for equilibrium
N-mg+ma=0
N=m(g-a)
N=56(10-2)=448N
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