Question

A man of mass 56 kg is standing on a weighing
machine kept on the floor of a lift which is moving
down with acceleration 2 m/s2. The apparent
weight of the man is (g = 10 m/s2)
(1) 700 N
(2) 660 N
(3) 560 N
(4) 448 N​

Answer 1

Explanation:

the answer is 3 560n I hope its help you

Answer 2

Answer:

448 N

Explanation:

Lift is moving down so a pseudo acceleration must work upward with same magnitude and for equilibrium

N-mg+ma=0

N=m(g-a)

N=56(10-2)=448N