A man of mass 60 kg carries a bag of fed 60n on his shoulder the force with which the floor push up his feet will be
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Answer:
647.584N
Explanation:
Given
Weight of man = 60kg
Weight of bag in men carries on his shoulder = 60N
To find
Force with which the floor
pushes up his feet = ?
Solution
We know that,
Weight of bag = 60N
G × mass of bag = 60N
Where G is the acceleration due to gravity = 9.8 sq ms
Let
m1 = mass of bag
\begin{gathered}m1 = \frac{60}{9.8} \: kg \\ m1 = 6.08 \: kg\end{gathered}
m1=
9.8
60
kg
m1=6.08kg
m2 = mass of man i.e., 60 kg
Total mass of man and bag system = (60+6.08) kg
= 66.08 kg
Where,
N = Normal reaction that applies at static equilibrium
N = (m1 + m2) g
N = 66.08 × 9.8
N = 647.584
Therefore,
the force with which the floor
pushes up his feet = 647.584N
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