A man of mass 60 kg dives vertically downwards into a swimming pool from a tower of height 20 m. He was found to go down in water by 2 m and then started rising. Find the average resistance of the water. Neglect the resistance of air.
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Given : Mass of the man (m) = 60 kg and height of the tower (h) = 20 mLetP= Average resistance of the water
We know that potential energy of the man before jumping= mgh= 60 × 9.8 × 20 = 11 760 N-m...
(i)and work done by the average resistance of water= Average resistance of water × Depth of water= P× 2 = 2 P N-m..
(ii)Since the total potential energy of the man is used in the work done by the water, thereforeequating equations
(i) and
(ii),11 760 = 2 Por117605880 N2P =Ans.
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