A man of mass 60 kg is riding in a lift . The weights of the man , when the lift is accelerating upwards and downwards at 2 m/s^2 are respectively?g=10 m/s^2
Anonymous:
complete question
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what to calculate then
The weight of the man..
Answers
Answered by
65
[1]
When lift is moving upwards
Weight = m(g + a)
= 60 kg × (10 + 2) m/s²
= 720 N
[2]
When lift is moving downwards
Weight = m(g - a)
= 60 kg × (10 - 2) m/s²
= 480 N
When lift is moving upwards
Weight = m(g + a)
= 60 kg × (10 + 2) m/s²
= 720 N
[2]
When lift is moving downwards
Weight = m(g - a)
= 60 kg × (10 - 2) m/s²
= 480 N
Answered by
76
Hi Friend,
When the lift moves upwards,the new force acts with the net force.
=mg +ma
=m(g+a)
=60(10+2)
=60(12)
F=720 N
When the body acts against the gravity, the new force tends to decrease the net force.
=m(g-a)
= 60(10-2)
=60(8)
F=480N
Hope this helped you a little!!!!!!!
When the lift moves upwards,the new force acts with the net force.
=mg +ma
=m(g+a)
=60(10+2)
=60(12)
F=720 N
When the body acts against the gravity, the new force tends to decrease the net force.
=m(g-a)
= 60(10-2)
=60(8)
F=480N
Hope this helped you a little!!!!!!!
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