Question

A man of mass 60 kg stands on a weighing machine of area 225 m square. The pressure exerted by him is ?(g is equals to 10m^-2)

Answer 1

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Formula to be used.
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$\bf \: = > pressure(p) = \frac{force(f)}{area(a)} \\ \\ \bf \: = > force \:(f) = mass(m) \times acceleration(g)$
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Given:-
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$\bf \: = > area(a) = 225 \: \: {m}^{2} \\ \\ \bf = > \: mass (m) = 60 \: \: kg \\ \\ \bf = > acceleration \: \: or \: \: gravity(g) = 10 \: m \: {s}^{ - 2}$
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So,

$\bf \: = > pressure(p) = \frac{f}{a} = \frac{m \times g}{a} \\ \\ \bf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{60 \times 10}{225} = \frac{8}{3 } = 2.66 \: pa$
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Answer 2

Hey there !

Solution:

Formula to be used:

• Weight = Mass × Gravity

Given Information:

• Mass = 60 kg
• Area = 225 m²

To Find:

• Pressure = ?

Illustration:

Weight = Mass × Gravity

=> Weight = 60 × 10 = 600 kg

Pressure = Weight / Area

=> Pressure = 600 Kg / 225 m²

=> Pressure = 2.66 Pa

Hence the pressure exerted is 2.66 Pa.

Hope my answer helps !