Question

A man of mass 60kg climbs up a 20m long staircase to the top of the building of height 10m high.What is the work done by him?

Answer 1

Work is defined as:

W=FdW=Fd

Work is also defined as:

W=FΔdW=FΔd

Force is defined as:

F=maF=ma

Force is also defined as:

F=mgF=mg

The integration of work is defined as:

W=∫2010FdxW=∫1020Fdx

The inverse of the integration of work (differentiation of force) is defined as:

F=dWdxF=dWdx

We can derive the formula defined as:

W=(mg)ΔdW=(mg)Δd

Now, solve for the work of the object using the values given and using the formula derived above:

W=(60kg⋅10m/s2)(20m−10m)W=(60kg⋅10m/s2)(20m−10m)

W=(600kg⋅m/s2)(10m)W=(600kg⋅m/s2)(10m)

W=6000JW=6000J

∴W=6000J


Hope it helps you
Please make me as brainliest