Physics, asked by koushikrao077, 6 months ago

a man of mass 60kg uses a rope to climb which which bears only 720N the maximum acceleration with which he can climb safely?​

Answers

Answered by Anonymous
4

Given :-

Mass of the man = 60 kg

Force applied on the object = 720 N

To Find :-

The maximum acceleration with which he can climb safely.

Analysis :-

Here, we are given with mass and the force.

Substitute the given values in the formula of force and find the acceleration accordingly.

Solution :-

We know that,

  • m = Mass
  • a = Acceleration
  • f = Force

Using the formula,

\underline{\boxed{\sf Force=Mass \times Acceleration}}

Given that,

Force (f) = 720 N

Mass (m) = 60 kg

Substituting their values,

720 = 60 × a

By transposing,

a = 720/60

a = 12 m/s²

Therefore,  the maximum acceleration with which he can climb safely is 12 m/s².

Answered by eins86
0

Given :-

Mass of the man = 60 kg

Force applied on the object = 720 N

To Find :-

The maximum acceleration with which he can climb safely.

Analysis :-

Here, we are given with mass and the force.

Substitute the given values in the formula of force and find the acceleration accordingly.

Solution :-

We know that,

m = Mass

a = Acceleration

f = Force

Using the formula,

Force=Mass×Acceleration

Given that,

Force (f) = 720 N

Mass (m) = 60 kg

Substituting their values,

720 = 60 × a

By transposing,

a = 720/60

a = 12 m/s²

Therefore, the maximum acceleration with which he can climb safely is 12 m/s².

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