Physics, asked by aryansukla7227, 1 year ago

a man of mass 65 kg holding bucket of mass 15 kg he walks 50 m on road at constant speed 3m/s and then climb hill of height 20m then work done by man taking g=10​

Answers

Answered by mukul2003
3

for constant speed on straight road wd =0

so wd by man = mgh = 80*10*20=160000Jor 16KJ


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aryansukla7227: 16kj
Answered by pkumarjee2006ouxd5c
4

No work is done on the level road as he is moving with constant speed

.(W=∆K=0)

Work done up the hill

W=mgh=(65+15)(10)(20)

=16000J


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