Question

A man of mass 70 kg and a boy of mass 30 kg dive of the end of a boat, of mass 150 kg with a horizontal velocity of 2 m/s relative to the boat. If initially, the boat is at rest, find its velocity

Answer 1

When the boat is initially at rest its velocity is Vb = - 1.33 m/s.

Explanation:

Given data:

Mass of the man "M" = 70 Kg

Mass of the boy "m" = 30 Kg

Mass of the boat "Mb"= 150 Kg

Relative velocity of jump with boat "v" = 2 m/s

Solution:

Now applying the law of conservation of momentum.

( m + M ) v + Mbvb = 0

( 30 + 70) 2 + 150 Vb = 0

Vb = - 1.33 m/s

Hence when the boat is initially at rest its velocity is Vb = - 1.33 m/s.

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