A man of mass 70kg jumps to a height of 50cm. His potential energy will be energy at the highest point is(g = 10 m/s2);
A. 3500J
B. 350J
C. 35J
D. none of these
Answers
Answered by
0
Answer:
PE= mgh
M= 70kg
g= 10 m/s^2
h= 50cm= 0.5m
PE= 70×10×0.5
= 70×5
= 350J (B)
Answered by
31
★ Question Given :
- A man of mass 70 kg jumps to a height of 50 cm. His potential energy at the highest point is(g = 10 m/s2)
★ Required Solution :
✫ Value Given to us :
- ⇢ Mass of Man = 70 kg
- ⇢ Height jumped up = 0.5 m
- ⇢ g Value = 10 m/s²
✫ Formula Used Here :
- ⇢ Potential Energy = mgh
★ Where :
- ⇢ m = Mass
- ⇢ g = Accelerating due to gravity
- ⇢ h = Height
✫ Putting Value in Formula :
- ⇢ Potential energy = mgh
- ⇢ P. E = 70 × 10 × 0.5
- ⇢ P.E = 350 Joule
✰ Potential Energy is 350 J ✰
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Anonymous:
Awesome as always :)
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