Question

a man of mass 75 kg is standing on the floor of a lift if left is accelerated upward with uniform acceleration two meter per second square what is a present weight of man inside lift​

Answer 1

Answer:

The FBD diagram as shown

Let floor exert a normal force acting on the man is N and its acceleration is 2ms

−2

N−750N=75×2N

⇒N=900N

solution

Answer 2

Answer:

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Explanation:

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