A man of mass 80 kg in a lift is moving upwards with an velocity of 8 m/sec and is brought to rest over a distance of 20 m . Find the force exerted on the man by the floor of elevator g = 10 m/ s^2
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mass =80kg
height = 20m
acceleration due to gravity=10m/s²
potential energy = mgh
80*10*20
16000j
we know
work done = energy
work done = force * distance
16000 = f * 20
16000/20= f
800 = force✔✔✔
I hope it will help ❤:-):-)
don't forget to mark the answer as brainliests answer ;-);-)❤
height = 20m
acceleration due to gravity=10m/s²
potential energy = mgh
80*10*20
16000j
we know
work done = energy
work done = force * distance
16000 = f * 20
16000/20= f
800 = force✔✔✔
I hope it will help ❤:-):-)
don't forget to mark the answer as brainliests answer ;-);-)❤
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