a man of mass 80 kg is riding on the small cut of mass 40 kg with is rolling along a level of power flow at speed of 2 metre second he is running on the cards so that his velocity unit with regard to give the question in the direction opposite to the motion card what is the speed of the centre of mass of the system
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hey mate here is ur ans ☺
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нєу тнєяє ιѕ αиѕωєя !!!
ι нσρє уσυ υи∂єяѕтαи∂ !!!
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Dear вαву !!
Given− Mass of man M1=80 kg , Mass of cart M2=40 kgVelocity of man with respect to ground=2−3=−1 m/sVelocity of cart with respect to ground=2 m/sConsider two cases according to your query1− if initially man was seated on the cart and then starts running then there will be no change in the velocity of CM and it will be VCM=2 m/s2−If man jump on the cart and then starts running then VCM is given byVCM=M1V1+M2V2M1+M2=80×(−1)+40×280+40=0 m/s
Regards.
ι нσρє уσυ υи∂єяѕтαи∂ !!!
=======================≠
Dear вαву !!
Given− Mass of man M1=80 kg , Mass of cart M2=40 kgVelocity of man with respect to ground=2−3=−1 m/sVelocity of cart with respect to ground=2 m/sConsider two cases according to your query1− if initially man was seated on the cart and then starts running then there will be no change in the velocity of CM and it will be VCM=2 m/s2−If man jump on the cart and then starts running then VCM is given byVCM=M1V1+M2V2M1+M2=80×(−1)+40×280+40=0 m/s
Regards.
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