Question

A man of mass 80 kg is standing inside a lift moving upward with a uniform
velocity of 4 m/s then the apparent weight (in N) of the person will be:-​

Answer 1

Answer:

$\textsf{1120}$

Explanation:

$\textsf{Given :-}$

$m = 80kg$

$a = 4m/{s}^{2}$

$g = 10m/{s}^{2}$

$from \: the \: free \: body \: diagram$

$R - mg = ma$

$R = m(g + a)$

$R = 80(4 + 10)$

$R = 1120$

$\textsf{so , the apparent weight of the person}$

$\textsf{is 1120N}$

$\LARGE \textsf{ Know more :-}$

• Acceleration, rate at which velocity changes with time, in terms of both speed and direction.

• it is a vector quantity.