Question

a man of mass 80 program is running and the constant acceleration of 0.55 metre per second square what is the force required to stop the man​

Answer 1

$\huge{\mathfrak{\underline{\red{Answer!}}}}$

44

$\huge{\mathfrak{\underline{\red{Explanation!}}}}$

we know that

force = mass × acceleration

= 80×0.55

= 44kgm/s²

Answer 2

Yo

The opposing force should be equal to the force applied by man ie

F=ma

=80*0.55

=44 N

Hope this helps