A man of Mass 80kg carried a block of mass 20 kg through a height of 10 m calculate the work done by this man in joules (g=10m|s2)
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Answered by
0
Explanation:
work done=change in energy
here potential energy changes
p.e=mgh
so work done=20*10*10=2000J
Answered by
1
- Mass of the man = 80 kg
- Mass of the block = 20 kg
- Acceleration due to gravity = 10 m/s²
Here, mass loaded by the man, F = (80 + 20) = 100 kg
Force = ma = 100 × 10 = 1000 N
Work done by the man, i.e., W = F × s = 1000 × 10
= 10000 J
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