Physics, asked by acharyajash, 8 months ago

A man of mass 84 kg stands upright on a floor.If the area of contact of his shoes and floor is 420 cm 2 ,determine the pressure he exerts on the floor.(take g=10 m/s^2)
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Answers

Answered by suveda34
10

Answer:

pressure = force/area

= 840/0.042 = 20,000 NM^-2

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Answered by shoovamjena15
7

Mass= 84kg

area of the contact of his shoes and floor is 420cm^2=4.2m^2

g =10m/s^2

We know that pressure is equal to force/ area and force is equal to mass *g.

So, we need to find the force first

So, force =mass*g=84*10=840N. (the S.I. unit of force is Newton or N) Therefore, pressure=840/4.2=200 N/m^2 (the S.I. unit of pressure is Pascal or N/m^2 )

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