a man of mass m is standing on the floor of a lift find his apparent weight when the lift is (i) Moving upward with uniform acceleration a. (ii) moving downward with uniform velocity v. Take the acceleration due to gravity equals to g
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When lift accelerates up, pseudo force acts downwards, hence it increases apparent weight. [a-e]
When lift accelerates down, pseudo force acts upwards, hence it decreases apparent weight [b-h]
When lift moves with uniform velocity there is no pseudo force, hence there is no change in weight. [c-g]
When lift falls freely, it accelerates with g downwards, causing an upwards pseudo force in the frame of the lift equal to mg. Hence total force is 0. So weight is 0. [d-f]
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