A man of mass m kg stands on a weighing machine in a lift .What would be the reading on the scale if the lift is moving up with an acceleration of a ms^-2 ?
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Given:
Mass of the man standing on the weighing machine = m kg
The acceleration of the lift in the upward direction = a m/s^2
To find:
The reading of the scale of the weighing machine.
Solution :
When the lift is moving upwards with an acceleration of a m/s^2 then using the Newton's laws of motion, the equation of force is given as:
N + mg = ma
N = ma - mg
N = m(g-a) Newton
The reading on the scale will be m(g-a) Newton.
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