Question

A man of mass m stands on a frame of mass M.
He pulls on a light rope, which passes over a
pulley. The other end of the rope is attached to
the frame. For the system to be in equilibrium,
what force must the man exert on the rope ?​

Answer 1

Answer:

Explanation:

Let T is the tension exerted by man on the rope , N is normal reaction between man and frame .

see free body diagram of frame :  

at equilibrium,  

upward force =  downward force  

T = N + Mg ......(1)

see free body diagram of man:  

upward force = downward force  

T + N = mg  

T = mg - N ......(2)

from equation (1) and (2),  

T = (m + M)g/2  

hence, force is exerted by man on the rope is (m + M)g/2

Answer 2

hey mate...

here is your answer...

Let T is the tension exerted by man on the rope , N is normal reaction between man and frame .

see free body diagram of frame :

at equilibrium,

upward force =  downward force

T = N + Mg ......(1)

see free body diagram of man:

upward force = downward force

T + N = mg

T = mg - N ......(2)

from equation (1) and (2),

T = (m + M)g/2

hence, force is exerted by man on the rope is (m + M)g/2

hope it helps...