Question

A man of mass m stands on a frame of mass m. He pulls on a light rope, which passes over a pulley. The other end of the rope is attached to the frame. For the system to be in equillibrium, what force must the man exert on the rope?

Answer 1

Let T is the tension exerted by man on the rope , N is normal reaction between man and frame .

see free body diagram of frame :

at equilibrium,

upward force =  downward force

T = N + Mg ......(1)

see free body diagram of man:

upward force = downward force

T + N = mg

T = mg - N ......(2)

from equation (1) and (2),

T = (m + M)g/2

hence, force is exerted by man on the rope is (m + M)g/2

Answer 2

Answer:

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